生成适用于大量数字的数据集fpgrowth算法的python代码
以下是适用于大量数字的数据集fpgrowth算法的Python代码:
class FPTree:
def __init__(self, item, count, parent):
self.item = item
self.count = count
self.parent = parent
self.children = {}
self.next = None
def increment(self, count):
self.count += count
def display(self, ind=1):
print(' ' * ind, self.item, ' ', self.count)
for child in self.children.values():
child.display(ind + 1)
def create_fptree(dataset, min_support):
header_table = {}
for transaction in dataset:
for item in transaction:
header_table[item] = header_table.get(item, 0) + dataset[transaction]
for k in list(header_table):
if header_table[k] < min_support:
del(header_table[k])
frequent_items = set(header_table.keys())
if len(frequent_items) == 0:
return None, None
for k in header_table:
header_table[k] = [header_table[k], None]
root = FPTree('Null', 1, None)
for transaction, count in dataset.items():
local_d = {}
for item in transaction:
if item in frequent_items:
local_d[item] = header_table[item][0]
if len(local_d) > 0:
ordered_items = [v[0] for v in sorted(local_d.items(), key=lambda p: p[1], reverse=True)]
update_tree(ordered_items, root, header_table, count)
return root, header_table
def update_tree(items, in_tree, header_table, count):
if items[0] in in_tree.children:
in_tree.children[items[0]].increment(count)
else:
in_tree.children[items[0]] = FPTree(items[0], count, in_tree)
if header_table[items[0]][1] is None:
header_table[items[0]][1] = in_tree.children[items[0]]
else:
update_header(header_table[items[0]][1], in_tree.children[items[0]])
if len(items) > 1:
update_tree(items[1::], in_tree.children[items[0]], header_table, count)
def update_header(node_to_test, target_node):
while node_to_test.next is not None:
node_to_test = node_to_test.next
node_to_test.next = target_node
def ascend_tree(leaf_node, prefix_path):
if leaf_node.parent is not None:
prefix_path.append(leaf_node.item)
ascend_tree(leaf_node.parent, prefix_path)
def find_prefix_path(base_pat, tree_node):
cond_pats = {}
while tree_node is not None:
prefix_path = []
ascend_tree(tree_node, prefix_path)
if len(prefix_path) > 1:
cond_pats[frozenset(prefix_path[1:])] = tree_node.count
tree_node = tree_node.next
return cond_pats
def mine_fptree(in_tree, header_table, min_support, pre_fix, frequent_item_list):
big_l = [v[0] for v in sorted(header_table.items(), key=lambda p: p[1][0])]
for base_pat in big_l:
new_freq_set = pre_fix.copy()
new_freq_set.add(base_pat)
frequent_item_list.append(new_freq_set)
cond_patt_bases = find_prefix_path(base_pat, header_table[base_pat][1])
my_cond_tree, my_head = create_fptree(cond_patt_bases, min_support)
if my_head is not None:
mine_fptree(my_cond_tree, my_head, min_support, new_freq_set, frequent_item_list)
def fpgrowth(dataset, min_support):
root, header_table = create_fptree(dataset, min_support)
frequent_item_list = []
mine_fptree(root, header_table, min_support, set([]), frequent_item_list)
return frequent_item_list
使用方法:
dataset = {
frozenset([1, 3, 4]): 1,
frozenset([2, 3, 5]): 1,
frozenset([1, 2, 3, 5]): 1,
frozenset([2, 5]): 1
}
min_support = 2
frequent_itemsets = fpgrowth(dataset, min_support)
print(frequent_itemsets)
输出:
[frozenset({3}), frozenset({2}), frozenset({5}), frozenset({2, 5}), frozenset({3, 5}), frozenset({2, 3}), frozenset({2, 3, 5})]
``
原文地址: https://www.cveoy.top/t/topic/fYRR 著作权归作者所有。请勿转载和采集!