Python贪吃蛇小游戏代码示例
Python贪吃蛇小游戏代码示例
想学习如何用Python编写一个简单的贪吃蛇小游戏吗?这篇文章提供了一个使用pygame库的代码示例,非常适合初学者学习游戏开发的基本概念。
import pygame
import time
import random
pygame.init()
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
display_width = 800
display_height = 600
gameDisplay = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('贪吃蛇')
clock = pygame.time.Clock()
snake_block = 10
snake_speed = 30
font_style = pygame.font.SysFont(None, 50)
score_font = pygame.font.SysFont(None, 35)
def our_snake(snake_block, snake_list):
for x in snake_list:
pygame.draw.rect(gameDisplay, black, [x[0], x[1], snake_block, snake_block])
def message(msg, color):
mesg = font_style.render(msg, True, color)
gameDisplay.blit(mesg, [display_width / 6, display_height / 3])
def gameLoop():
game_over = False
game_close = False
x1 = display_width / 2
y1 = display_height / 2
x1_change = 0
y1_change = 0
snake_List = []
Length_of_snake = 1
foodx = round(random.randrange(0, display_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, display_height - snake_block) / 10.0) * 10.0
while not game_over:
while game_close == True:
gameDisplay.fill(white)
message('你输了!按Q退出或者C重新开始', red)
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q:
game_over = True
game_close = False
if event.key == pygame.K_c:
gameLoop()
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block
x1_change = 0
if x1 >= display_width or x1 < 0 or y1 >= display_height or y1 < 0:
game_close = True
x1 += x1_change
y1 += y1_change
gameDisplay.fill(white)
pygame.draw.rect(gameDisplay, red, [foodx, foody, snake_block, snake_block])
snake_Head = []
snake_Head.append(x1)
snake_Head.append(y1)
snake_List.append(snake_Head)
if len(snake_List) > Length_of_snake:
del snake_List[0]
for x in snake_List[:-1]:
if x == snake_Head:
game_close = True
our_snake(snake_block, snake_List)
pygame.display.update()
if x1 == foodx and y1 == foody:
foodx = round(random.randrange(0, display_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, display_height - snake_block) / 10.0) * 10.0
Length_of_snake += 1
clock.tick(snake_speed)
pygame.quit()
quit()
gameLoop()
这段代码使用了pygame库来创建游戏窗口、绘制图形和处理用户输入等。它展示了如何创建游戏循环、处理游戏逻辑以及检测碰撞等基本的游戏开发概念。
希望这个代码示例能够帮助你开始学习Python游戏开发。如果你有任何问题,请随时在评论区留言。
原文地址: https://www.cveoy.top/t/topic/fP7A 著作权归作者所有。请勿转载和采集!