NETLINK_XFRM用户层获取SA的C代码
以下是NETLINK_XFRM用户层获取SA的C代码示例:
#include <linux/xfrm.h>
#include <linux/netlink.h>
#include <linux/socket.h>
#include <linux/rtnetlink.h>
int main() {
struct sockaddr_nl nladdr;
struct nlmsghdr *nlh;
struct msghdr msg;
struct iovec iov;
int sock_fd, len;
char buffer[4096];
struct {
struct nlmsghdr nlh;
struct xfrm_userpolicy_info up;
} req;
memset(&nladdr, 0, sizeof(nladdr));
nladdr.nl_family = AF_NETLINK;
sock_fd = socket(PF_NETLINK, SOCK_RAW, NETLINK_XFRM);
if (sock_fd < 0) {
perror("socket");
return -1;
}
if (bind(sock_fd, (struct sockaddr *)&nladdr, sizeof(nladdr)) < 0) {
perror("bind");
close(sock_fd);
return -1;
}
memset(&req, 0, sizeof(req));
req.nlh.nlmsg_len = NLMSG_LENGTH(sizeof(req.up));
req.nlh.nlmsg_flags = NLM_F_REQUEST | NLM_F_DUMP;
req.nlh.nlmsg_type = XFRM_MSG_GETPOLICY;
req.up.sel.family = AF_INET;
req.up.sel.sport = htons(1234);
req.up.sel.dport = htons(5678);
nlh = &req.nlh;
iov.iov_base = (void *)nlh;
iov.iov_len = nlh->nlmsg_len;
memset(&msg, 0, sizeof(msg));
msg.msg_name = &nladdr;
msg.msg_namelen = sizeof(nladdr);
msg.msg_iov = &iov;
msg.msg_iovlen = 1;
if (sendmsg(sock_fd, &msg, 0) < 0) {
perror("sendmsg");
close(sock_fd);
return -1;
}
do {
len = recv(sock_fd, buffer, sizeof(buffer), 0);
if (len < 0) {
perror("recv");
close(sock_fd);
return -1;
}
for (nlh = (struct nlmsghdr *)buffer; NLMSG_OK(nlh, len);
nlh = NLMSG_NEXT(nlh, len)) {
if (nlh->nlmsg_type == NLMSG_DONE) {
close(sock_fd);
return 0;
} else if (nlh->nlmsg_type == NLMSG_ERROR) {
perror("NLMSG_ERROR");
close(sock_fd);
return -1;
} else if (nlh->nlmsg_type == XFRM_MSG_NEWSA) {
struct xfrm_usersa_info *usa = NLMSG_DATA(nlh);
printf("New SA: spi=%u\n", usa->id.proto.spi);
} else if (nlh->nlmsg_type == XFRM_MSG_DELSA) {
struct xfrm_usersa_info *usa = NLMSG_DATA(nlh);
printf("Deleted SA: spi=%u\n", usa->id.proto.spi);
}
}
} while (1);
close(sock_fd);
return 0;
}
该示例代码通过NETLINK_XFRM套接字通信协议,向内核发送XFRM_MSG_GETPOLICY消息来获取安全策略,然后接收内核返回的消息并解析其中的安全关联信息。在接收到消息时,根据消息类型来处理安全关联信息,可以获取到新建或删除的安全关联的SPI
原文地址: https://www.cveoy.top/t/topic/fJ7p 著作权归作者所有。请勿转载和采集!