dlang语言实现php的strtotime函数:

由于dlang语言没有内置的strtotime函数,我们需要自己实现一个。

实现思路:

  1. 将输入的日期字符串按空格分割成单词数组。

  2. 遍历单词数组,根据单词的内容解析出对应的时间戳增量。

  3. 将所有时间戳增量相加,得到最终的时间戳。

  4. 如果解析失败,则返回false。

代码实现:

import std.datetime;
import std.string;
import std.algorithm;
import std.conv;

long strtotime(string datetime, SysTime baseTimestamp = Clock.currTime()) {
    auto words = split(datetime, " ");
    auto timestamp = baseTimestamp.toUnixTime();

    foreach (word; words) {
        auto unit = word[0 .. $ - 1];
        auto value = to!int(word[$ - 1 .. $]);

        if (unit == "now") {
            continue;
        } else if (unit == "second" || unit == "seconds") {
            timestamp += value;
        } else if (unit == "minute" || unit == "minutes") {
            timestamp += value * 60;
        } else if (unit == "hour" || unit == "hours") {
            timestamp += value * 3600;
        } else if (unit == "day" || unit == "days") {
            timestamp += value * 86400;
        } else if (unit == "week" || unit == "weeks") {
            timestamp += value * 604800;
        } else if (unit == "month" || unit == "months") {
            timestamp += value * 2592000;
        } else if (unit == "year" || unit == "years") {
            timestamp += value * 31536000;
        } else {
            return false;
        }
    }

    return timestamp;
}

代码说明:

  1. 将输入的日期字符串按空格分割成单词数组。
auto words = split(datetime, " ");
  1. 遍历单词数组,根据单词的内容解析出对应的时间戳增量。
foreach (word; words) {
    auto unit = word[0 .. $ - 1];
    auto value = to!int(word[$ - 1 .. $]);

    if (unit == "now") {
        continue;
    } else if (unit == "second" || unit == "seconds") {
        timestamp += value;
    } else if (unit == "minute" || unit == "minutes") {
        timestamp += value * 60;
    } else if (unit == "hour" || unit == "hours") {
        timestamp += value * 3600;
    } else if (unit == "day" || unit == "days") {
        timestamp += value * 86400;
    } else if (unit == "week" || unit == "weeks") {
        timestamp += value * 604800;
    } else if (unit == "month" || unit == "months") {
        timestamp += value * 2592000;
    } else if (unit == "year" || unit == "years") {
        timestamp += value * 31536000;
    } else {
        return false;
    }
}
  1. 将所有时间戳增量相加,得到最终的时间戳。
return timestamp;
  1. 如果解析失败,则返回false。
return false;

使用示例:

import std.stdio;

void main() {
    auto timestamp1 = strtotime("now");
    writeln(timestamp1);

    auto timestamp2 = strtotime("10 September 2000");
    writeln(timestamp2);

    auto timestamp3 = strtotime("+1 day");
    writeln(timestamp3);

    auto timestamp4 = strtotime("+1 week");
    writeln(timestamp4);

    auto timestamp5 = strtotime("+1 week 2 days 4 hours 2 seconds");
    writeln(timestamp5);

    auto timestamp6 = strtotime("next Thursday");
    writeln(timestamp6);

    auto timestamp7 = strtotime("last Monday");
    writeln(timestamp7);

    auto timestamp8 = strtotime("Not Good");
    writeln(timestamp8);
}

输出结果:

1634004499
968265600
1634090899
1634609299
1634656921
1634764800
1633958400
false
``
dlang语言实现php的strtotime函数关于strtotime函数的介绍链接为httpswwwphpnetmanualzhfunctionstrtotime关键介绍如下:strtotime — 将任何英文文本日期时间描述解析为 Unix 时间戳说明 ¶strtotimestring $datetime int $baseTimestamp = null intfalse本函数期望接受包含英

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