#include stdiohunion myun struct int xyzu; ink k;a;void main aux=4; auy=5; quz=6; ak=7; printfdnaux; printfdnsizeofa;

There are a few errors in this code:

1. The data type ink is not defined. It should be int.
2. The line q.u.z=6; should be a.u.z=6;.
3. The main() function should have a return type of int.
4. The format specifier in the printf() statements should be %d\n, not %d/n.

Here is the corrected code:

#include <stdio.h>

union myun
{
   struct {int x,y,z;} u;
   int k;
} a;

int main()
{
  a.u.x = 4;
  a.u.y = 5;
  a.u.z = 6;
  a.k = 7;

  printf("%d\n", a.u.x);
  printf("%d\n", sizeof(a));

  return 0;
}

This code declares a union myun that contains a struct u with three integers x, y, and z, and an integer k. In the main() function, it assigns values to a.u.x, a.u.y, a.u.z, and a.k, and then prints the value of a.u.x and the size of the a union. The output should be:

4
4
``