The output of this code would be:

0 2 4

Explanation:

  • An array of size 3 is created with all elements initialized to 0 by default.
  • The first loop starts from index 1 and goes up to the second last index (since the last index is already initialized to 0), and sets each element to twice the value of its index.
  • The second loop prints out all elements of the array.
  • Therefore, the output would be 0 2 4.
public static void mainStringargsint nums=new int3;forint i=1;inumslength;i++numsi=i2;forint i=0;inumslength;i++Systemoutprintnumsi;

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