The output of this program will be:

6 12

Explanation:

  • We declare a union called myun which contains a struct with three integers x, y, and z, as well as a single integer k.
  • In the main function, we assign values to a.u.x, a.u.y, and a.u.z, as well as a.k.
  • When we print a.u.x, we get the value of 6 instead of 4 because the value of a.k overwrote the values of a.u.x, a.u.y, and a.u.z.
  • The sizeof(a) statement prints the size of the union a, which is 12 bytes since the struct inside the union occupies 3 integers, each taking up 4 bytes
#include stdiohunion myun struct int x y z; u; int k; a;int main aux = 4; auy = 5; auz = 6; ak = 7; printfdn aux; printfdn sizeofa; return 0;

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