用java编写sumlimits^n_i=1fracx_iy_itimes1000timesfrac1n

double sum = 0; for (int i = 0; i < n; i++) { sum += x[i] / y[i]; } double result = sum * 1000 / n;

$用java编写sumlimits^n_i=1fracx_iy_itimes1000timesfrac1n$

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