用ros编写代码实现产生两只乌龟A、B、C键盘控制A 运动时 A、B、C 会始终保持等边三角形的编队边 长为1且朝向一致我想要cpp代码
以下是使用ROS编写的cpp代码,实现产生两只乌龟A、B、C,键盘控制A运动时,A、B、C会始终保持等边三角形的编队,边长为1,且朝向一致。
#include <ros/ros.h>
#include <geometry_msgs/Twist.h>
#include <turtlesim/Pose.h>
#include <math.h>
#define PI 3.14159265
ros::Publisher turtleA_pub;
ros::Publisher turtleB_pub;
ros::Publisher turtleC_pub;
ros::Subscriber turtleA_sub;
turtlesim::Pose turtleA_pose;
turtlesim::Pose turtleB_pose;
turtlesim::Pose turtleC_pose;
void turtleAPoseCallback(const turtlesim::Pose::ConstPtr& pose_msg)
{
turtleA_pose = *pose_msg;
}
void moveTurtleA(double speed, double distance, bool isForward)
{
geometry_msgs::Twist vel_msg;
if(isForward)
{
vel_msg.linear.x = abs(speed);
}
else
{
vel_msg.linear.x = -abs(speed);
}
vel_msg.linear.y = 0;
vel_msg.linear.z = 0;
vel_msg.angular.x = 0;
vel_msg.angular.y = 0;
vel_msg.angular.z = 0;
double current_distance = 0.0;
ros::Rate loop_rate(10);
while(current_distance < distance)
{
turtleA_pub.publish(vel_msg);
double x_diff = turtleA_pose.x - turtleB_pose.x;
double y_diff = turtleA_pose.y - turtleB_pose.y;
double angle_diff = atan2(y_diff, x_diff) - turtleA_pose.theta;
if(angle_diff > PI)
{
angle_diff -= 2 * PI;
}
else if(angle_diff < -PI)
{
angle_diff += 2 * PI;
}
vel_msg.angular.z = 4 * angle_diff;
turtleB_pub.publish(vel_msg);
turtleC_pub.publish(vel_msg);
ros::spinOnce();
loop_rate.sleep();
current_distance = sqrt(pow(turtleA_pose.x - turtleB_pose.x, 2) + pow(turtleA_pose.y - turtleB_pose.y, 2));
}
vel_msg.linear.x = 0;
vel_msg.angular.z = 0;
turtleA_pub.publish(vel_msg);
}
int main(int argc, char **argv)
{
ros::init(argc, argv, "turtle_triangular_formation");
ros::NodeHandle nh;
turtleA_pub = nh.advertise<geometry_msgs::Twist>("turtle1/cmd_vel", 10);
turtleB_pub = nh.advertise<geometry_msgs::Twist>("turtle2/cmd_vel", 10);
turtleC_pub = nh.advertise<geometry_msgs::Twist>("turtle3/cmd_vel", 10);
turtleA_sub = nh.subscribe("turtle1/pose", 10, turtleAPoseCallback);
ros::Rate loop_rate(10);
double speed, distance;
bool isForward;
ROS_INFO("Enter speed: ");
std::cin >> speed;
ROS_INFO("Enter distance: ");
std::cin >> distance;
ROS_INFO("Forward? (1/0): ");
std::cin >> isForward;
moveTurtleA(speed, distance, isForward);
return 0;
}
``
原文地址: https://www.cveoy.top/t/topic/fDNu 著作权归作者所有。请勿转载和采集!