用roscpp编写代码实现产生两只乌龟A、B、C键盘控制A 运动时 A、B、C 会始终保持等边三角形的编队边 长为1且朝向一致
以下是实现代码:
#include <ros/ros.h>
#include <geometry_msgs/Twist.h>
// 定义全局变量
geometry_msgs::Twist vel_a, vel_b, vel_c;
ros::Publisher pub_a, pub_b, pub_c;
void keyboardCallback(const geometry_msgs::Twist::ConstPtr& msg)
{
// 控制乌龟A的运动
vel_a.linear.x = msg->linear.x;
vel_a.angular.z = msg->angular.z;
// 计算乌龟B和C的位置
vel_b.linear.x = vel_c.linear.x = vel_a.linear.x;
vel_b.angular.z = vel_a.angular.z - 2.0944; // 2π/3
vel_c.angular.z = vel_a.angular.z + 2.0944; // 2π/3
// 发布速度指令
pub_a.publish(vel_a);
pub_b.publish(vel_b);
pub_c.publish(vel_c);
}
int main(int argc, char** argv)
{
// 初始化ROS节点
ros::init(argc, argv, "turtle_triangle");
ros::NodeHandle nh;
// 创建三个乌龟的速度发布者
pub_a = nh.advertise<geometry_msgs::Twist>("turtle1/cmd_vel", 1);
pub_b = nh.advertise<geometry_msgs::Twist>("turtle2/cmd_vel", 1);
pub_c = nh.advertise<geometry_msgs::Twist>("turtle3/cmd_vel", 1);
// 创建键盘控制乌龟A的订阅者
ros::Subscriber sub = nh.subscribe<geometry_msgs::Twist>("turtle1/cmd_vel", 1, keyboardCallback);
// 设置乌龟B和C的初始位置
vel_b.linear.x = vel_c.linear.x = 1;
vel_b.angular.z = -2.0944; // 2π/3
vel_c.angular.z = 2.0944; // 2π/3
// 发布初始速度指令
pub_b.publish(vel_b);
pub_c.publish(vel_c);
// 进入ROS循环
ros::spin();
return 0;
}
需要注意的是,该代码需要在启动三个乌龟节点之后才能正常运行。可以使用以下命令启动三个乌龟节点:
rosrun turtlesim turtlesim_node
rosrun turtlesim turtlesim_node __name:=turtle2
rosrun turtlesim turtlesim_node __name:=turtle3
然后再运行上述代码即可。使用键盘控制乌龟A的运动,乌龟B和C会始终保持等边三角形的编队,边长为1,且朝向一致
原文地址: https://www.cveoy.top/t/topic/fDM0 著作权归作者所有。请勿转载和采集!