基于地理位置和信誉值的商品分配算法
import pandas as pd
import math
def normalize(x, min_val, max_val):
return (x - min_val) / (max_val - min_val)
for jishu in range(1, 32):
# 加载商品信息表和会员信息表
product_info = pd.read_excel('D:\pythonProject3\商品信息\商品打包.xlsx')
member_info = pd.read_excel('D:\pythonProject3\打包问题\会员信息.xlsx', sheet_name=f'会员信息{jishu}')
# 对商品信息表按照经纬度排序
product_info.sort_values(by=['新商品GPS经度', '新商品GPS纬度'], inplace=True)
# 初始化会员挑选到商品的数量
member_info['挑选商品数量'] = 0
# 遍历每个会员
for i in range(len(member_info)):
member = member_info.iloc[i]
# 获取会员的GPS经纬度
member_latitude = member['会员GPS纬度']
member_longitude = member['会员GPS经度']
# 获取会员的预订商品限额
limit = member['预订商品限额']
# 初始化商品数量和总距离
selected_quantity = 0
total_distance = 0
# 遍历每个商品
for j in range(len(product_info)):
product = product_info.iloc[j]
# 获取商品的GPS经纬度和打包数量
product_latitude = product['新商品GPS纬度']
product_longitude = product['新商品GPS经度']
quantity = product['打包数量']
# 计算商品与会员之间的距离
distance = math.sqrt(
(member_latitude - product_latitude) ** 2 + (member_longitude - product_longitude) ** 2)
# 判断商品与会员之间的距离是否满足要求
if distance <= 1:
# 判断挑选该商品是否会超过预订商品限额
if selected_quantity + quantity <= limit:
# 更新商品数量和总距离
selected_quantity += quantity
total_distance += distance
else:
break
# 更新会员挑选到商品的数量
member_info.at[i, '挑选商品数量'] = selected_quantity
# 归一化信誉值
min_val = member_info['信誉值'].min()
max_val = member_info['信誉值'].max()
member_info['信誉值'] = member_info['信誉值'].apply(lambda x: normalize(x, min_val, max_val))
# 输出每个会员挑选到商品的数量
print(member_info['挑选商品数量'])
# member_info.to_excel('D:\pythonProject3\打包问题\会员信息 - 副本4.xlsx', index=False, columns=['会员编号', '会员GPS纬度', '会员GPS经度', '信誉值', '预订商品比例', '挑选商品数量'])
outfile = r'D:\pythonProject3\打包问题\会员信息 - 副本4.xlsx'
with pd.ExcelWriter(outfile, mode='a', engine='openpyxl') as writer:
member_info.to_excel(writer, columns=['会员编号', '会员GPS纬度', '会员GPS经度', '信誉值', '预订商品比例',
'挑选商品数量'], sheet_name=f'会员信息{jishu}', index=False)
原文地址: https://www.cveoy.top/t/topic/fAw4 著作权归作者所有。请勿转载和采集!