Flink 连接流实现支付对账:代码示例
以下是基于 Flink 连接流 connect 实现两个流支付对账的代码实现示例:
import org.apache.flink.api.common.functions.CoGroupFunction;
import org.apache.flink.api.java.tuple.Tuple2;
import org.apache.flink.streaming.api.datastream.ConnectedStreams;
import org.apache.flink.streaming.api.environment.StreamExecutionEnvironment;
import org.apache.flink.util.Collector;
public class PaymentReconciliation {
public static void main(String[] args) throws Exception {
StreamExecutionEnvironment env = StreamExecutionEnvironment.getExecutionEnvironment();
// 创建第一个流,包含支付信息
ConnectedStreams<Tuple2<String, Double>, Tuple2<String, Double>> paymentStream = env.fromElements(
Tuple2.of("user1", 100.0),
Tuple2.of("user2", 200.0),
Tuple2.of("user3", 300.0)
).connect(env.fromElements(
Tuple2.of("user1", 100.0),
Tuple2.of("user2", 150.0),
Tuple2.of("user4", 200.0)
));
// 使用connect连接两个流,并指定CoGroupFunction进行对账处理
paymentStream
.keyBy(0) // 按照用户ID进行分组
.coGroup(paymentStream.keyBy(0))
.where(t -> t.f0)
.equalTo(t -> t.f0)
.window(TumblingEventTimeWindows.of(Time.seconds(5)))
.apply(new PaymentReconciliationFunction())
.print();
env.execute("Payment Reconciliation");
}
public static class PaymentReconciliationFunction implements CoGroupFunction<Tuple2<String, Double>, Tuple2<String, Double>, String> {
@Override
public void coGroup(Iterable<Tuple2<String, Double>> first, Iterable<Tuple2<String, Double>> second, Collector<String> out) throws Exception {
double totalPayment = 0.0;
double totalReceived = 0.0;
for (Tuple2<String, Double> payment : first) {
totalPayment += payment.f1;
}
for (Tuple2<String, Double> received : second) {
totalReceived += received.f1;
}
if (totalPayment == totalReceived) {
out.collect("Payment and received amounts match");
} else {
out.collect("Payment and received amounts do not match");
}
}
}
}
在上述代码中,我们创建了两个包含支付信息的流,并使用 connect 方法将它们连接在一起。然后,我们使用 keyBy 方法按照用户 ID 进行分组,并使用 CoGroupFunction 对账处理。在 CoGroupFunction 的实现中,我们分别计算了两个流中的支付总额和收款总额,并判断它们是否相等。最后,我们使用 print 方法将结果打印出来。
请注意,上述代码仅为示例,实际使用时需要根据实际情况进行调整和优化。
原文地址: http://www.cveoy.top/t/topic/eyju 著作权归作者所有。请勿转载和采集!