n=intinput请输入n我们将给出斐波那契额数列前n项a b = 1 1printabsep=end=for i in rangen -22 a=a+b b=a+b printabsep=if n2==1 printa+b怎么样让输出结果为一行

n=int(input("请输入n,我们将给出斐波那契额数列前n项")) a, b = 1, 1 print(a,b,sep=",",end=",") for i in range((n -2)//2): a=a+b b=a+b print(a,b,sep=",",end=",") if n%2==1: print(a+b)