Consider the Bayesian network below where all variables are binaryM --- E --- C --- APM 05 PA 06M PEMT 05F 075E A PCEAT T 075T F

Using the chain rule of Bayesian networks, we have:

P(M=T, E=T, A=F, C=T) = P(M=T) * P(E=T|M=T) * P(A=F) * P(C=T|E=T, A=F)

From the given probabilities:

P(M=T) = 0.5 P(E=T|M=T) = 0.5 P(A=F) = 0.4 (since P(A=T) = 0.6) P(C=T|E=T, A=F) = 0.6

Therefore:

P(M=T, E=T, A=F, C=T) = 0.5 * 0.5 * 0.4 * 0.6 = 0.06

So the probability of M=T, E=T, A=F, C=T is 0.06.