Four consecutive odd integers have a sum of 64 Find the integers

Let x be the first odd integer. Then the next three consecutive odd integers are x+2, x+4, and x+6. We know that the sum of these four integers is 64, so we can write an equation:

x + (x+2) + (x+4) + (x+6) = 64

Simplifying and solving for x, we get:

4x + 12 = 64 4x = 52 x = 13

Therefore, the four consecutive odd integers are 13, 15, 17, and 19.