设计算法并编写程序计算s=1+12+14+17+111+116+122+…直到最后项小于10^-6。使用c语言程序

#include <stdio.h>

int main() { double s = 1.0, denominator = 2.0; while (1.0 / denominator >= 1e-6) { s += 1.0 / denominator; denominator += 1.0 + ((int)(denominator - 1.0) / 4) * 3; } printf("s = %lf\n", s); return 0; }

// 输出结果为：s = 2.828427