Given the digraph as shown below is the altering sequence v3 a2 v1 a6 v2 a4 v4 a8 v5 a walkhttpscorexjtlueducnpluginfilephp535211questionquestiontext2444812151221435Q_AlteringSeqpng

No, the sequence is not a walk because there is no edge labeled "a()" in the graph.

原文地址: https://www.cveoy.top/t/topic/drkK 著作权归作者所有。请勿转载和采集!