怎样使用正则表达式将abcd1234 abcd1234 void abcd1234 abcd1234切割为:abcd1234abcd1234void abcd1234 abcd1234?
可以使用正则表达式的分组功能来实现:
import re
s1 = "abcd1234*"
s2 = "abcd1234*"
s3 = "void (*)(abcd1234*, abcd1234*)"
pattern = r'(.*)' # 匹配任意字符
result1 = re.findall(pattern, s1)[0]
result2 = re.findall(pattern, s2)[0]
result3 = re.findall(pattern, s3)[0]
print(result1)
print(result2)
print(result3)
输出:
abcd1234*
abcd1234*
void (*)(abcd1234*, abcd1234*)
原文地址: https://www.cveoy.top/t/topic/dn7C 著作权归作者所有。请勿转载和采集!