编写一段代码从输入的描述C语言函数原型的字符串中获取函数的参数类型其中如果参数为函数标记参数类型为function如果是指针标记为pointer；需通过以下测试用例：assert get_param_typesint foochar int == pointer intassert get_param_typesvoid barint float double == pointer float d

assert (get_param_types("void func(int, char*, float**)") == ["int", "pointer", "pointer"]) assert (get_param_types("int f(int()(int, char**), float*)") == ["function", "pointer"]) assert (get_param_types("void g(void()(int, double), char*, int)") == ["function", "pointer", "int"]) assert (get_param_types("double h(int**, float()(char), void()(void))") == ["pointer", "function", "function"])