class Solution def __init__self selfdirs = -1 0 1 0 0 1 0 -1 def bfsself grid i j q = i j area = 0 visited = while lenq!=0 area += 1 for
The above code is a solution to the problem of finding the maximum area of an island in a given grid of 0's and 1's.
The solution uses a breadth-first search (BFS) approach to traverse the grid and count the area of each island.
The BFS algorithm starts at a given cell (i, j) and explores its neighboring cells in four directions (up, down, left, right).
If a neighboring cell is also part of the island (i.e., contains a 1) and has not been visited before, it is added to the queue and marked as visited.
The algorithm continues until there are no more cells to explore, and the area of the island is returned.
The solution then iterates over all cells in the grid and applies the BFS algorithm to each cell that contains a 1.
The maximum area of all islands is returned as the final result.
Overall, the time complexity of the solution is O(m * n), where m and n are the dimensions of the grid, since each cell is visited at most once
原文地址: https://www.cveoy.top/t/topic/dHE2 著作权归作者所有。请勿转载和采集!