2计算数列123-234 345I -456…-1^ n-1n n+1n+2 --前n项的和其中 表示幂运算当第一次出现和数的绝对值大于3000时求和终止。用c语言解决问题

#include <stdio.h> #include <stdlib.h>

int main() { int n = 1; int sum = 0; int term = 1; while (abs(sum) <= 3000) { sum += term; term = term * (-1) * n * (n + 1) * (n + 2); n++; } printf("The sum is %d\n", sum); return 0; }