为了求解pi_t的表达式,我们需要对目标函数进行求导。首先,我们对指数函数进行求导,得到:

\frac{\partial}{\partial \pi_t} \left(K - De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\right) = De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma R_t

接着,我们对pi_t进行求导,得到:

\frac{\partial}{\partial \pi_t} \left(K - De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\right) = De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma R_t - De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma {r_t}

将两个导数相等,得到:

De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma R_t - De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma {r_t} = 0

化简得到:

De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma (R_t - {r_t}) = 0

因为De^{-\gamma\left[\left(w_t-\pi_t\right){r_t}+\pi_t R_t+c_t+\delta\left(q_t\right)-q_t z_t\right]}\gamma > 0,所以我们可以将上式化简为:

R_t - {r_t} = 0

因此,我们得到了pi_t的表达式:

pi_t = \frac{R_t}{r_t

K-De^-gammaleftleftw_t-pi_trightr_t+pi_t R_t+c_t+deltaleftq_tright-q_t z_tright对该latex式子求解由一阶最优化条件找到pi_t的表达式

原文地址: https://www.cveoy.top/t/topic/cfwn 著作权归作者所有。请勿转载和采集!

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