c语言简单计算sinx的近似值x的值通过输入得到

#include <stdio.h> #include <math.h>

int main() { double x, result = 0; int i, j, sign = 1; printf("请输入x的值（弧度）："); scanf("%lf", &x); for (i = 1; i <= 10; i += 2) { double temp = 1; for (j = 1; j <= i; j++) { temp *= x / j; } result += sign * temp; sign = -sign; } printf("sin(%.2f)的近似值为：%.4f\n", x, result); return 0; }