c++ 检测线与多边形关系
要检测一条直线与多边形之间的关系,需要进行以下步骤:
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将多边形的每个边与检测线进行交点计算,得到每个交点的坐标。
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对所有交点进行排序,按照从左到右的顺序排列。
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遍历每个交点,分别计算其左侧和右侧的交点个数。
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如果左侧和右侧交点个数都为奇数,则检测线与多边形相交;如果都为偶数,则检测线在多边形外部;如果一个为奇数,一个为偶数,则检测线与多边形相交于多边形的一个顶点。
以下是一个示例代码:
#include <iostream>
#include <vector>
using namespace std;
struct Point {
double x, y;
};
struct Line {
Point start, end;
};
// 计算两条线段的交点
Point getIntersection(Line l1, Line l2) {
double x1 = l1.start.x, y1 = l1.start.y, x2 = l1.end.x, y2 = l1.end.y;
double x3 = l2.start.x, y3 = l2.start.y, x4 = l2.end.x, y4 = l2.end.y;
double d = (x1 - x2) * (y3 - y4) - (y1 - y2) * (x3 - x4);
double x = ((x1 * y2 - y1 * x2) * (x3 - x4) - (x1 - x2) * (x3 * y4 - y3 * x4)) / d;
double y = ((x1 * y2 - y1 * x2) * (y3 - y4) - (y1 - y2) * (x3 * y4 - y3 * x4)) / d;
return {x, y};
}
// 计算多边形的边与线段的交点
vector<Point> getIntersectionPoints(Line l, vector<Line> edges) {
vector<Point> points;
for (auto edge : edges) {
Point p = getIntersection(l, edge);
if (p.x >= min(edge.start.x, edge.end.x) && p.x <= max(edge.start.x, edge.end.x)
&& p.y >= min(edge.start.y, edge.end.y) && p.y <= max(edge.start.y, edge.end.y)) {
points.push_back(p);
}
}
return points;
}
// 判断点是否在多边形内部
bool isPointInsidePolygon(Point p, vector<Point> vertices) {
bool inside = false;
for (int i = 0, j = vertices.size() - 1; i < vertices.size(); j = i++) {
if (((vertices[i].y > p.y) != (vertices[j].y > p.y)) &&
(p.x < (vertices[j].x - vertices[i].x) * (p.y - vertices[i].y) / (vertices[j].y - vertices[i].y) + vertices[i].x)) {
inside = !inside;
}
}
return inside;
}
// 检测线段与多边形的关系
bool isLineInsidePolygon(Line l, vector<Point> vertices) {
vector<Point> points = getIntersectionPoints(l, getEdges(vertices));
sort(points.begin(), points.end(), [](Point a, Point b) { return a.x < b.x; });
int leftCount = 0, rightCount = 0;
for (auto point : points) {
if (point.x < l.start.x) {
leftCount++;
} else if (point.x > l.end.x) {
rightCount++;
}
}
if (leftCount % 2 == 0 && rightCount % 2 == 0) {
return false;
} else if (leftCount % 2 == 1 && rightCount % 2 == 1) {
return true;
} else {
return isPointInsidePolygon(l.start, vertices) || isPointInsidePolygon(l.end, vertices);
}
}
// 获取多边形的边
vector<Line> getEdges(vector<Point> vertices) {
vector<Line> edges;
for (int i = 0, j = vertices.size() - 1; i < vertices.size(); j = i++) {
edges.push_back({vertices[j], vertices[i]});
}
return edges;
}
int main() {
vector<Point> polygon = {{0, 0}, {2, 0}, {2, 2}, {1, 3}, {0, 2}};
Line line1 = {{0, 1}, {3, 1}}; // 与多边形相交
Line line2 = {{-1, 1}, {1, 1}}; // 在多边形外部
Line line3 = {{0, 0}, {2, 2}}; // 与多边形相交于顶点
cout << isLineInsidePolygon(line1, polygon) << endl; // 1
cout << isLineInsidePolygon(line2, polygon) << endl; // 0
cout << isLineInsidePolygon(line3, polygon) << endl; // 1
return 0;
}
``
原文地址: https://www.cveoy.top/t/topic/cIQA 著作权归作者所有。请勿转载和采集!