java 求s=a+aa+aaa+aaa的值要求：控制台输入1-9数字例如输入1计算过程是 1例如输入2计算过程是 2+22例如输入3计算过程是 3+33+333输出最后结果即可

import java.util.Scanner;

public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("请输入1-9之间的数字："); int a = scanner.nextInt(); int sum = 0; int temp = 0; for(int i = 1; i <= a; i++) { temp = temp * 10 + a; sum += temp; } System.out.println("s=" + sum); } }