void main int a = 1 b = 2 m = 0 n = 0 k; k = n=bam=ab; printfk = dm = dnkm;

The output of this program is:

k = 1, m = 1

Explanation:

1. The variables a, b, m, n are initialized to 1, 2, 0, 0 respectively.

2. The expression (n=b>a)||(m=a<b) is evaluated using the OR operator ||.

3. The sub-expression b>a is true (since 2 is greater than 1), so the assignment n=b>a sets n to 1 (true).

4. Since the OR operator short-circuits, the second sub-expression (m=a<b) is not evaluated, and k is assigned the value of the first sub-expression (i.e. 1).

5. Finally, m is assigned the value of a<b, which is also true (since 1 is less than 2), so m is set to 1.

6. The printf statement outputs the values of k and m, which are 1 and 1 respectively.