在这段代码中帮我补全一下代码使得这段代码能够使用Thistlethwaite实现魔方的复原给出完整的case GREEN部分的代码#include iostream#include vector#include stringusing namespace std; 定义魔方的颜色enum Color RED BLUE GREEN WHITE YELLOW ORANGE ; 定义魔方的转动方式en

在 case GREEN: 的部分，需要按照类似的方式实现 green 面的旋转逻辑，即根据旋转方式调整 green 面的状态。具体实现如下：

case GREEN: // 根据旋转方式调整 green 面的状态 for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { temp[i][j] = up[2-j][i]; } } if (rotation == CLOCKWISE) { for (int i = 0; i < 3; i++) { up[0][i] = front[0][i]; front[0][i] = down[0][i]; down[0][i] = back[2][2-i]; back[2][2-i] = temp[0][i]; } for (int i = 0; i < 3; i++) { up[1][i] = front[1][i]; front[1][i] = down[1][i]; down[1][i] = back[1][2-i]; back[1][2-i] = temp[1][i]; } for (int i = 0; i < 3; i++) { up[2][i] = front[2][i]; front[2][i] = down[2][i]; down[2][i] = back[0][2-i]; back[0][2-i] = temp[2][i]; } } else if (rotation == COUNTERCLOCKWISE) { for (int i = 0; i < 3; i++) { up[0][i] = back[2][2-i]; back[2][2-i] = down[0][i]; down[0][i] = front[0][i]; front[0][i] = temp[0][i]; } for (int i = 0; i < 3; i++) { up[1][i] = back[1][2-i]; back[1][2-i] = down[1][i]; down[1][i] = front[1][i]; front[1][i] = temp[1][i]; } for (int i = 0; i < 3; i++) { up[2][i] = back[0][2-i]; back[0][2-i] = down[2][i]; down[2][i] = front[2][i]; front[2][i] = temp[2][i]; } } else if (rotation == DOUBLE) { for (int i = 0; i < 3; i++) { up[0][i] = down[0][i]; down[0][i] = temp[0][i]; } for (int i = 0; i < 3; i++) { up[1][i] = down[1][i]; down[1][i] = temp[1][i]; } for (int i = 0; i < 3; i++) { up[2][i] = down[2][i]; down[2][i] = temp[2][i]; } for (int i = 0; i < 3; i++) { front[0][i] = back[2][2-i]; back[2][2-i] = temp[0][i]; } for (int i = 0; i < 3; i++) { front[1][i] = back[1][2-i]; back[1][2-i] = temp[1][i]; } for (int i = 0; i < 3; i++) { front[2][i] = back[0][2-i]; back[0][2-i] = temp[2][i]; } } break;