如果要读取GB2312编码的JSON文件,可以使用以下代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define BUFFER_SIZE 1024

int main() {
    char buffer[BUFFER_SIZE];
    FILE *file = fopen("data.json", "rb");
    if (file == NULL) {
        printf("Failed to open file\n");
        return 1;
    }
    size_t bytesRead;
    while ((bytesRead = fread(buffer, 1, BUFFER_SIZE, file)) > 0) {
        // Convert GB2312 to UTF-8
        char *utf8 = (char *)malloc(bytesRead * 3 + 1);
        size_t utf8Length = gb2312_to_utf8(buffer, bytesRead, utf8, bytesRead * 3 + 1);
        utf8[utf8Length] = '\0';
        // Parse JSON
        cJSON *json = cJSON_Parse(utf8);
        if (json == NULL) {
            printf("Failed to parse JSON\n");
            free(utf8);
            fclose(file);
            return 1;
        }
        // Do something with the JSON
        // ...
        cJSON_Delete(json);
        free(utf8);
    }
    fclose(file);
    return 0;
}

size_t gb2312_to_utf8(const char *gb2312, size_t gb2312Length, char *utf8, size_t utf8Size) {
    iconv_t converter = iconv_open("UTF-8", "GB2312");
    if (converter == (iconv_t)-1) {
        printf("Failed to open converter\n");
        return 0;
    }
    size_t utf8Length = utf8Size - 1;
    char *inPtr = (char *)gb2312;
    char *outPtr = utf8;
    size_t inBytesLeft = gb2312Length;
    size_t outBytesLeft = utf8Length;
    size_t result = iconv(converter, &inPtr, &inBytesLeft, &outPtr, &outBytesLeft);
    if (result == -1) {
        printf("Conversion error\n");
        utf8Length = 0;
    } else {
        utf8Length = utf8Size - outBytesLeft - 1;
    }
    *outPtr = '\0';
    iconv_close(converter);
    return utf8Length;
}

这个代码片段使用了iconv库将GB2312编码的字符串转换为UTF-8编码的字符串,并使用cJSON库解析JSON字符串。注意,这个代码片段假设文件中的JSON对象不会跨越多个缓冲区。如果要处理这种情况,需要使用额外的代码来拼接缓冲区中的字符串。

c语言 读取json 文件 文件时GB2312的

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