输入三个数计算并输出它们的平均数。保留小数点后6位 C语言

#include <stdio.h>

int main() { double num1, num2, num3; double average;

printf("请输入三个数：");
scanf("%lf %lf %lf", &num1, &num2, &num3);

average = (num1 + num2 + num3) / 3;

printf("它们的平均数为：%.6lf\n", average);

return 0;

}