要使用geatpy库中的NSGA2算法解决VRP问题,需要定义一个问题类来描述问题的特征和参数。以下是一个示例问题类的定义:

import numpy as np
import geatpy as ea

class VRPProblem(ea.Problem):
    def __init__(self, n_customers, capacity, demands, distances):
        name = 'VRPProblem'
        M = 2  # 目标维数
        maxormins = [1, 1]  # 目标最大化或最小化标记,1表示最小化,-1表示最大化
        Dim = n_customers  # 决策变量维数
        varTypes = np.array([0] * Dim)  # 决策变量类型,0表示实数
        lb = np.array([0] * Dim)  # 决策变量下界
        ub = np.array([n_customers - 1] * Dim)  # 决策变量上界
        lbin = [1] * Dim  # 决策变量是否包含下界
        ubin = [1] * Dim  # 决策变量是否包含上界
        self.capacity = capacity  # 车辆容量
        self.demands = demands  # 顾客需求量
        self.distances = distances  # 顾客之间的距离矩阵
        self.n_customers = n_customers  # 顾客数量
        ea.Problem.__init__(self, name, M, maxormins, Dim, varTypes, lb, ub, lbin, ubin)

    def aimFunc(self, pop):
        # 计算目标函数值
        time_costs = np.zeros((pop.sizes, self.M))
        for i in range(pop.sizes):
            route = self.decode(pop.Phen[i, :])
            time_costs[i, 0] = np.max(np.cumsum([self.demands[j] for j in route]))
            time_costs[i, 1] = np.sum([self.distances[route[j - 1], route[j]] for j in range(1, len(route))])
        pop.ObjV = time_costs

    def decode(self, chromosome):
        # 将染色体解码成路径
        routes = []
        used_capacity = 0
        current_route = []
        for c in chromosome:
            if c == 0:
                if current_route:
                    routes.append(current_route)
                    current_route = []
            else:
                if used_capacity + self.demands[c] <= self.capacity:
                    used_capacity += self.demands[c]
                    current_route.append(c)
                else:
                    routes.append(current_route)
                    current_route = [c]
                    used_capacity = self.demands[c]
        routes.append(current_route)
        return [0] + [j for route in routes for j in route] + [0]

    def calDistances(self, locations):
        # 计算顾客之间的距离矩阵
        n = len(locations)
        distances = np.zeros((n, n))
        for i in range(n):
            for j in range(n):
                distances[i, j] = np.linalg.norm(locations[i] - locations[j])
        return distances

该问题类包含以下成员函数:

  • __init__(self, n_customers, capacity, demands, distances): 初始化问题类,其中n_customers表示顾客数量,capacity表示车辆容量,demands表示顾客需求量,distances表示顾客之间的距离矩阵。
  • aimFunc(self, pop): 计算目标函数值,其中pop表示种群对象,pop.Phen是种群表现型矩阵,pop.ObjV是种群目标函数值矩阵。
  • decode(self, chromosome): 将染色体解码成路径,其中chromosome是染色体。
  • calDistances(self, locations): 计算顾客之间的距离矩阵,其中locations是顾客的坐标矩阵。

在使用时,可以先创建一个问题对象,然后调用NSGA2算法对象的run方法求解:

n_customers = 10
capacity = 20
demands = np.random.randint(1, 10, n_customers)
locations = np.random.rand(n_customers, 2)
distances = VRPProblem.calDistances(locations)
problem = VRPProblem(n_customers, capacity, demands, distances)
algorithm = ea.nsga2(problem)
algorithm.run()
用PYthon里面的geatpy库里的NSGA2算法解决VRP问题如何定义问题类

原文地址: https://www.cveoy.top/t/topic/bM8u 著作权归作者所有。请勿转载和采集!

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