用PYthon里面的geatpy库里的NSGA2算法解决VRP问题如何定义问题类
要使用geatpy库中的NSGA2算法解决VRP问题,需要定义一个问题类来描述问题的特征和参数。以下是一个示例问题类的定义:
import numpy as np
import geatpy as ea
class VRPProblem(ea.Problem):
def __init__(self, n_customers, capacity, demands, distances):
name = 'VRPProblem'
M = 2 # 目标维数
maxormins = [1, 1] # 目标最大化或最小化标记,1表示最小化,-1表示最大化
Dim = n_customers # 决策变量维数
varTypes = np.array([0] * Dim) # 决策变量类型,0表示实数
lb = np.array([0] * Dim) # 决策变量下界
ub = np.array([n_customers - 1] * Dim) # 决策变量上界
lbin = [1] * Dim # 决策变量是否包含下界
ubin = [1] * Dim # 决策变量是否包含上界
self.capacity = capacity # 车辆容量
self.demands = demands # 顾客需求量
self.distances = distances # 顾客之间的距离矩阵
self.n_customers = n_customers # 顾客数量
ea.Problem.__init__(self, name, M, maxormins, Dim, varTypes, lb, ub, lbin, ubin)
def aimFunc(self, pop):
# 计算目标函数值
time_costs = np.zeros((pop.sizes, self.M))
for i in range(pop.sizes):
route = self.decode(pop.Phen[i, :])
time_costs[i, 0] = np.max(np.cumsum([self.demands[j] for j in route]))
time_costs[i, 1] = np.sum([self.distances[route[j - 1], route[j]] for j in range(1, len(route))])
pop.ObjV = time_costs
def decode(self, chromosome):
# 将染色体解码成路径
routes = []
used_capacity = 0
current_route = []
for c in chromosome:
if c == 0:
if current_route:
routes.append(current_route)
current_route = []
else:
if used_capacity + self.demands[c] <= self.capacity:
used_capacity += self.demands[c]
current_route.append(c)
else:
routes.append(current_route)
current_route = [c]
used_capacity = self.demands[c]
routes.append(current_route)
return [0] + [j for route in routes for j in route] + [0]
def calDistances(self, locations):
# 计算顾客之间的距离矩阵
n = len(locations)
distances = np.zeros((n, n))
for i in range(n):
for j in range(n):
distances[i, j] = np.linalg.norm(locations[i] - locations[j])
return distances
该问题类包含以下成员函数:
__init__(self, n_customers, capacity, demands, distances): 初始化问题类,其中n_customers表示顾客数量,capacity表示车辆容量,demands表示顾客需求量,distances表示顾客之间的距离矩阵。aimFunc(self, pop): 计算目标函数值,其中pop表示种群对象,pop.Phen是种群表现型矩阵,pop.ObjV是种群目标函数值矩阵。decode(self, chromosome): 将染色体解码成路径,其中chromosome是染色体。calDistances(self, locations): 计算顾客之间的距离矩阵,其中locations是顾客的坐标矩阵。
在使用时,可以先创建一个问题对象,然后调用NSGA2算法对象的run方法求解:
n_customers = 10
capacity = 20
demands = np.random.randint(1, 10, n_customers)
locations = np.random.rand(n_customers, 2)
distances = VRPProblem.calDistances(locations)
problem = VRPProblem(n_customers, capacity, demands, distances)
algorithm = ea.nsga2(problem)
algorithm.run()
原文地址: https://www.cveoy.top/t/topic/bM8u 著作权归作者所有。请勿转载和采集!