a) Using the formula $PV = \frac{FV}{(1+\frac{r}{n})^{nt}}$, where $FV$ is the future value, $r$ is the annual interest rate, $n$ is the number of times compounded per year, and $t$ is the number of years:

$PV = \frac{3500}{(1+\frac{0.089}{12})^{12\cdot5}} \approx \boxed{2476.61}$

b) Using the same formula with $r = 0.066$, $n = 4$, and $t = 8$:

$PV = \frac{3500}{(1+\frac{0.066}{4})^{4\cdot8}} \approx \boxed{2189.86}$

c) Using the same formula with $r = 0.043$, $n = 365$, and $t = 4$:

$PV = \frac{3500}{(1+\frac{0.043}{365})^{365\cdot4}} \approx \boxed{3040.22}$

d) Using the formula $PV = FVe^{-rt}$, where $e$ is the mathematical constant approximately equal to 2.71828:

$PV = 3500e^{-0.057\cdot3} \approx \boxed{3007.27}$

4Find the present value of $3500 under each of the following rates and periodsa89 per cent compounded monthly for 5 yearsb66 per cent compounded quarterly for 8 yearsc43 per cent compounded daily for

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