The standard-Binet IQ test is designed so that scores are normally distributed with a mean of 100 and a standard deviation of 16 A person got an IQ score of 135 What is the percentile rank for an IQ o

We can use the z-score formula to find the percentile rank:

z = (x - μ) / σ

where x is the IQ score, μ is the mean, and σ is the standard deviation.

Plugging in the values:

z = (135 - 100) / 16 = 2.1875

Using a standard normal distribution table or calculator, we can find that the percentile rank for a z-score of 2.1875 is approximately 98.0%.

Therefore, the person's IQ score of 135 is at the 98th percentile. This means that the person scored higher than 98% of the population who took the test.