x²-150x+5525=0

To solve for x in the equation x²-150x+5525=0, we can use the quadratic formula:

x = (-b ± √(b²-4ac)) / 2a

In this case, a = 1, b = -150, and c = 5525. Plugging these values into the formula, we get:

x = (150 ± √(150²-4(1)(5525))) / 2(1) x = (150 ± √(22500-22100)) / 2 x = (150 ± √400) / 2 x = (150 ± 20) / 2

So x can be either:

x = (150 + 20) / 2 = 85

or

x = (150 - 20) / 2 = 65

Therefore, the solutions to the equation x²-150x+5525=0 are x = 85 and x = 65.