从键盘上输入任意一个数x判定该数是否满足x4若满足则输出YES否则输出NO

Python代码：

x = float(input())
if abs(x) > 4:
    print("YES")
else:
    print("NO")

Java代码：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        double x = scanner.nextDouble();
        if (Math.abs(x) > 4) {
            System.out.println("YES");
        } else {
            System.out.println("NO");
        }
    }
}

C++代码：

#include <iostream>
#include <cmath>

using namespace std;

int main() {
    double x;
    cin >> x;
    if (abs(x) > 4) {
        cout << "YES" << endl;
    } else {
        cout << "NO" << endl;
    }
    return 0;
}