const uniqueNames = [...new Set(arr.map(item => item.name))]; const nameCount = uniqueNames.map(name => { return { name: name, count: arr.filter(item => item.name === name).length }; }); nameCount.sort((a, b) => b.count - a.count); console.log(nameCount); // 输出按数量排序的name列表

let arr = name m1 groupName group1 type Messense_Mutation name m1 groupName group2 type Messense_Mutation

原文地址: https://www.cveoy.top/t/topic/Y5w 著作权归作者所有。请勿转载和采集!

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