Here's an algorithm to find the median value using at most O(logn) queries:

  1. Start by querying the middle value, n/2, from both databases. Let's call these values A and B respectively.

  2. If A < B, it means that the median value is either in the second half of database A or the first half of database B. So, we can discard the first half of database A and the second half of database B.

  3. If B < A, it means that the median value is either in the second half of database B or the first half of database A. So, we can discard the first half of database B and the second half of database A.

  4. Repeat steps 2 and 3 recursively on the remaining halves of the databases until we find the median.

  5. Once we have narrowed down the search to a single value in each database, we can query both of them to find the smaller of the two values. This will be the median.

This algorithm works because in each step, we discard half of the values from one of the databases. This reduces the search space by half in each iteration, leading to a logarithmic number of queries.

The overall time complexity of this algorithm is O(logn) because in each step, we are reducing the search space by half.

Efficient Median Finding from Two Databases with Logarithmic Queries

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