给出一个不多于3位的正整数 n 要求：求出它是几位数；分别打印出每一位数字数字之间加一个空格;按逆序打印出各位数字数字之间加一个空格用devc++

#include <iostream>
using namespace std;

int main() {
    int n;
    cin >> n;
    int count = 0; // 记录位数
    int temp = n;
    while (temp > 0) {
        count++;
        temp /= 10;
    }
    cout << "位数：" << count << endl;
    cout << "每位数字：";
    for (int i = count; i > 0; i--) {
        int digit = n / pow(10, i-1);
        cout << digit << " ";
        n %= (int)pow(10, i-1);
    }
    cout << endl;
    cout << "逆序数字：";
    while (n > 0) {
        int digit = n % 10;
        cout << digit << " ";
        n /= 10;
    }
    cout << endl;
    return 0;
}