计算正整数2345的各位数字平方和c语言代码

#include <stdio.h> #include <math.h>

int main() { int num = 2345; int sum = 0; while(num > 0) { int digit = num % 10; sum += pow(digit, 2); num /= 10; } printf("The sum of squares of digits of 2345 is: %d", sum); return 0; }