C语言实现斐波那契数列计算

#include<stdio.h>

int main() {
    int i;
    printf("Please select a number to be printed: ");
    scanf("%d", &i);

    int fib[i];
    fib[0] = 0;
    fib[1] = 1;

    for (int j = 2; j <= i; j++) {
        fib[j] = fib[j - 1] + fib[j - 2];
    }

    printf("The number is %d\n", fib[i]);

    return 0;
}