C++ 编程题：奇偶数之和判断 - 帮助禾木判定胜负

#include using namespace std;

int main() { int a; cin >> a;

int sum = 0;
while (a > 0) {
    sum += a % 10;
    a /= 10;
}

if (sum % 2 == 0) {
    cout << "taozi" << endl;
} else {
    cout << "wulahu" << endl;
}

return 0;

}