Java 链表反转:高效算法实现
以下是一个 Java 实现的方法,可以将给定链表反转:
class ListNode {
int val;
ListNode next;
ListNode(int val) {
this.val = val;
}
}
public class ReverseLinkedList {
public static ListNode reverse(ListNode head) {
ListNode prev = null;
ListNode current = head;
ListNode next = null;
while (current != null) {
next = current.next;
current.next = prev;
prev = current;
current = next;
}
return prev;
}
public static void printList(ListNode head) {
ListNode current = head;
while (current != null) {
System.out.print(current.val + " -> ");
current = current.next;
}
System.out.println("null");
}
public static void main(String[] args) {
ListNode head = new ListNode(1);
ListNode node2 = new ListNode(2);
ListNode node3 = new ListNode(3);
ListNode node4 = new ListNode(4);
ListNode node5 = new ListNode(5);
head.next = node2;
node2.next = node3;
node3.next = node4;
node4.next = node5;
System.out.println("Original List:");
printList(head);
ListNode reversedHead = reverse(head);
System.out.println("Reversed List:");
printList(reversedHead);
}
}
输出结果为:
Original List:
1 -> 2 -> 3 -> 4 -> 5 -> null
Reversed List:
5 -> 4 -> 3 -> 2 -> 1 -> null
原文地址: http://www.cveoy.top/t/topic/p3MJ 著作权归作者所有。请勿转载和采集!