import os

a = 0 flag = input()

for i in range(len(flag)): a += 1

if a != 32: print('error') exit()

if flag[0] != 'f' or flag[1] != 'l' or flag[2] != 'a' or flag[3] != 'g' or flag[4] != '{' or flag[31] != '}': print('error') exit()

tmp = []

for i in range(a): tmp.append(ord(flag[i]) - 9)

for i in range(a): tmp[i] ^= 51

for i in range(a): tmp[i] += 8

tmp1 = tmp[a-3] tmp2 = tmp[a-2] tmp3 = tmp[a-1]

for i in range(a-3): tmp[i + tmp3 - 1] = tmp[i + tmp3 - 1] ^ tmp[i + tmp2 + 1]

tmp3 = 0 tmp2 = 1 tmp1 = 2

for i in range(a): if i % 7 == 1: continue tmp[i] ^= 119

with open('out', 'w') as f: f.write(str(''.join([chr(x) for x in tmp])))

Python代码:解密字符串

原文地址: http://www.cveoy.top/t/topic/osyK 著作权归作者所有。请勿转载和采集!

免费AI点我,无需注册和登录