C语言函数计算1+1/2+2/3+...+n/n+1的值

#include <stdio.h>

double fun(int n){ double s = 0; int i; for(i = 1; i <= n; i++){ s += (double)i/(i+1); } return s; }

int main(){ int n; printf('请输入正整数n：'); scanf('%d', &n); printf('s = %lf', fun(n)); return 0; }