The error message indicates that there is a KeyError when trying to access the value associated with the key 'assembly_line' in the dictionary sense_to_name.

To resolve this issue, you need to make sure that the dictionary sense_to_name contains the key 'assembly_line' and its corresponding value before accessing it. You can check if a key exists in a dictionary using the 'in' keyword. Here's an example:

if 'assembly_line' in sense_to_name:
    label_name = sense_to_name['assembly_line']
else:
    # handle the case when 'assembly_line' key is not found

Alternatively, you can use the get() method of dictionaries to retrieve the value associated with a key, and provide a default value to return if the key is not found. Here's an example:

label_name = sense_to_name.get('assembly_line', 'default_value')

Replace 'default_value' with the appropriate value or code to handle the case when the key 'assembly_line' is not found in the dictionary.

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