#include stdioh main int a=3b=2c=1; c-=++b; b=a+c; int b=5c=12; c=b2; a-=c;printfddd abc; a+=--c;printfdddn a b c;

The code provided is incomplete and contains syntax errors. Here is the corrected version:

#include <stdio.h>

int main() {
    int a = 3, b = 2, c = 1;
    c -= ++b;
    b *= a + c;
    {
        int b = 5, c = 12;
        c /= b * 2;
        a -= c;
        printf("%d,%d,%d,", a, b, c);
        a += --c;
        printf("%d,%d,%d\n", a, b, c);
    }
    return 0;
}

Explanation:

1. c -= ++b; - ++b increments the value of b by 1 and then assigns it to c. So, c becomes 3 and b becomes 3.
2. b *= a + c; - a + c evaluates to 6. The value of b is multiplied by 6, so b becomes 18.
3. Inside the inner block, int b = 5, c = 12; declares and initializes new variables b and c with values 5 and 12 respectively.
4. c /= b * 2; - b * 2 evaluates to 10. The value of c is divided by 10, so c becomes 1.
5. a -= c; - c is subtracted from a, so a becomes 2.
6. printf("%d,%d,%d,", a, b, c); prints the values of a, b, and c which are 2, 18, and 1 respectively.
7. a += --c; - --c decrements the value of c by 1 and then assigns it to a. So, c becomes 0 and a becomes 2.
8. printf("%d,%d,%d\n", a, b, c); prints the updated values of a, b, and c which are 2, 18, and 0 respectively.

Output: 2,18,1,2,18,