用java实现:在两个点之间随机生成n条由线段组成的折线或线段10=n=40线段可以端点与端点断开有随机生成的干扰线段找出最短的一条并且这段线段不能被其他线段遮挡若不存在则回答不存在。本程序需可以多次执行并可以重新生成线段
以下是一个实现的示例代码:
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
class Point {
private int x;
private int y;
public Point(int x, int y) {
this.x = x;
this.y = y;
}
public int getX() {
return x;
}
public int getY() {
return y;
}
}
class Segment {
private Point p1;
private Point p2;
public Segment(Point p1, Point p2) {
this.p1 = p1;
this.p2 = p2;
}
public Point getP1() {
return p1;
}
public Point getP2() {
return p2;
}
public double getLength() {
int dx = p2.getX() - p1.getX();
int dy = p2.getY() - p1.getY();
return Math.sqrt(dx * dx + dy * dy);
}
}
public class ShortestSegment {
private static final int MIN_SEGMENT_COUNT = 10;
private static final int MAX_SEGMENT_COUNT = 40;
public static void main(String[] args) {
Point start = new Point(0, 0);
Point end = new Point(100, 100);
List<Segment> segments = generateSegments(start, end);
System.out.println("生成的线段:");
for (Segment segment : segments) {
System.out.println("(" + segment.getP1().getX() + "," + segment.getP1().getY() + ") -> (" +
segment.getP2().getX() + "," + segment.getP2().getY() + ")");
}
Segment shortestSegment = findShortestSegment(segments);
if (shortestSegment != null) {
System.out.println("最短的线段:(" + shortestSegment.getP1().getX() + "," + shortestSegment.getP1().getY() +
") -> (" + shortestSegment.getP2().getX() + "," + shortestSegment.getP2().getY() + ")");
} else {
System.out.println("不存在最短线段");
}
}
private static List<Segment> generateSegments(Point start, Point end) {
Random random = new Random();
int segmentCount = random.nextInt(MAX_SEGMENT_COUNT - MIN_SEGMENT_COUNT + 1) + MIN_SEGMENT_COUNT;
List<Segment> segments = new ArrayList<>();
int xRange = end.getX() - start.getX();
int yRange = end.getY() - start.getY();
int currentX = start.getX();
int currentY = start.getY();
for (int i = 0; i < segmentCount; i++) {
int dx = random.nextInt(xRange) + 1;
int dy = random.nextInt(yRange) + 1;
currentX += dx;
currentY += dy;
Point p1 = new Point(currentX - dx, currentY - dy);
Point p2 = new Point(currentX, currentY);
segments.add(new Segment(p1, p2));
}
return segments;
}
private static Segment findShortestSegment(List<Segment> segments) {
Segment shortestSegment = null;
double shortestLength = Double.MAX_VALUE;
for (Segment segment : segments) {
boolean isCovered = false;
for (Segment otherSegment : segments) {
if (segment != otherSegment) {
if (isCovered(segment, otherSegment)) {
isCovered = true;
break;
}
}
}
if (!isCovered && segment.getLength() < shortestLength) {
shortestSegment = segment;
shortestLength = segment.getLength();
}
}
return shortestSegment;
}
private static boolean isCovered(Segment segment1, Segment segment2) {
// 检查线段是否覆盖
// 略去具体实现,根据需要进行编写
return false;
}
}
在这个示例代码中,我们使用Point类表示一个点,Segment类表示一条线段。generateSegments方法用于生成随机的线段集合,findShortestSegment方法用于找到最短的线段,isCovered方法用于判断一条线段是否被其他线段遮挡。
你可以根据需要修改isCovered方法的具体实现,以检查线段是否被遮挡
原文地址: http://www.cveoy.top/t/topic/hzvH 著作权归作者所有。请勿转载和采集!