帮我找绘制三分康托集的python代码

以下是绘制三分康托集的Python代码：

import matplotlib.pyplot as plt
import numpy as np

def ternary_cantor_set(n):
    if n == 0:
        return np.array([[0, 1]])
    else:
        previous_set = ternary_cantor_set(n-1)
        left_third = previous_set / 3
        right_third = (previous_set + 2) / 3
        middle_third = np.concatenate([left_third[:, 1:], right_third[:, :-1]], axis=1)
        return np.concatenate([left_third, middle_third, right_third], axis=1)

cantor_set = ternary_cantor_set(10)

plt.figure(figsize=(10, 5))
plt.plot(cantor_set[1], np.zeros_like(cantor_set[1]), 'o', markersize=1)
plt.title('Ternary Cantor Set')
plt.show()

这段代码将绘制一个三分康托集的图形，其中 n 变量控制迭代次数，值越大，生成的康托集就越详细