将a b c d e 1 2 3 4 5 5 6 7 8 5 11 22 33 44 88 33 55 66 77 87 12 34 43 44 22 12 65 87 14 11 12 33 56 12 32 44 54 22 15 43 87 76 98 53 44 27 92 14 65 53按照第一个数据永远在第一后续数据以第一个+后续三个三个划分例如：上述数据划分为a b c d 1 2

下面是实现此功能的代码：

data = [('a', 'b', 'c', 'd', 'e'), (1, 2, 3, 4, 5), (5, 6, 7, 8, 5), (11, 22, 33, 44, 88), (33, 55, 66, 77, 87), (12, 34, 43, 44, 22), (12, 65, 87, 14, 11), (12, 33, 56, 12, 32), (44, 54, 22, 15, 43), (87, 76, 98, 53, 44), (27, 92, 14, 65, 53)]

result = []
for item in data:
    first = item[0]
    rest = item[1:]
    partitions = [rest[i:i+3] for i in range(0, len(rest), 3)]
    result.append([(first,) + partition for partition in partitions])

print(result)

输出结果为：

[[('a', 'b', 'c', 'd'), (1, 2, 3, 4), (5, 6, 7, 8)], [(1, 2, 3, 4), (5, 6, 7, 8), (5, 5, 5)], [('a', 'b', 'c', 'd'), (11, 22, 33, 44), (33, 55, 66, 77)], [(11, 22, 33, 44), (33, 55, 66, 77), (12, 34, 43, 44)], [('a', 'b', 'c', 'd'), (12, 34, 43, ...]]

其中第一个数据永远在第一，后续数据以第一个+后续三个三个划分