cosπ4cost-sinπ4sint 结果可以化简成什么样

根据三角恒等式cos(π/4) = sin(π/4) = 1/√2，以及sin^2(θ) + cos^2(θ) = 1，可以进行化简。

cos(π/4) * cos(t) - sin(π/4) * sin(t) = (1/√2) * cos(t) - (1/√2) * sin(t) = (1/√2) * (cos(t) - sin(t)) = (1/√2) * (cos(t) - sin(t)) * (√2/√2) = (1/2) * (cos(t) - sin(t)) * √2 = (1/2) * (cos(t)√2 - sin(t)√2) = (1/2) * (√2 * (cos(t) - sin(t)))

因此，结果可以化简为(1/2) * (√2 * (cos(t) - sin(t)))。