758 What is the wavelength of a proton traveling at a speed of 621 kms What would be the region of the spectrum for electromagnetic radiation of this wavelength

We can use the de Broglie wavelength equation to find the wavelength of a proton:

λ = h / p

where λ is the wavelength, h is Planck's constant, and p is the momentum of the proton. We can find the momentum of the proton using the formula:

p = mv

where m is the mass of the proton and v is its velocity. We have:

m = 1.67 × 10^-27 kg (mass of a proton) v = 6.21 × 10^3 m/s (velocity of the proton)

So,

p = (1.67 × 10^-27 kg) × (6.21 × 10^3 m/s) = 1.04 × 10^-22 kg m/s

Now we can plug this into the de Broglie equation:

λ = h / p = (6.626 × 10^-34 J s) / (1.04 × 10^-22 kg m/s) = 6.38 × 10^-13 m

This wavelength corresponds to the range of gamma rays in the electromagnetic spectrum